BlueJ Program Displaying An Entered Full Name In Short Form

This is BlueJ program on string modification. User  entered name with middle name and surname which is stored in a string object will be displayed in short form. Initial alphabets of the name and middle name(s) and the complete surname will be displayed. The full name may have number of middle names. The initial alphabets of name, middle name and surname will be in capital letter and the rest of alphabets will be in lower case.

How to proceed on this string modification program

We have to recognize the initial alphabets of name, middlename and surname the entered name. The first alphabet of the string is the initial alphabet of the name and accessing it is not a tough job. Next initial alphabets should be just next to blank space as after name, middlename and surname there should be blank space. If user enters multiple consecutive blank spaces, it can be removed also.

So, in this BlueJ program we need to access the blank spaces from the string and the alphabet following the blank spaces are to be taken which will be the initial alphabet of either name, middlename or surname. If these initial alphabets are in lower case, they should be converted in to upper case. All the alphabets of the last word means the surname should be taken and the alphabets excepting the first one should be changed to lower case if required.

Codes of the string modification program

import java.io.*;

class Words2

{

 int sp;

 BufferedReader br;

 String text,text1="";

  public static void main(String args[])throws IOException

   {

  Words2 ob=new Words2();

 ob.accept();

 ob.result();

  }

  Words2()

  {

   br=new BufferedReader(new InputStreamReader(System.in));

   text="";

   sp=0;

  }

public void accept()throws IOException

{

 System.out.println("Enter the Name:");

 text=br.readLine().trim();

}

public void result()

{

int i=0,len,flag=0;

char ch;

System.out.println("The entered Name ="+text);

 len=text.length();

 do

 {

  if(text.charAt(i)==' ')

  sp++;

  i++;

 }while(i< len);

i=0;

do

{

ch=text.charAt(i);

 if(i==0)

 {

 if(ch >=97 && ch< =122)

 ch=(char)(ch-32);

 text1=text1+ch;

 }

 else if(ch==' ')

 {

  flag=1;

  text1=text1+".";

  sp--;

 }

 else if(flag==1)

 {

 if(ch >=97 && ch< =122)

 ch=(char)(ch-32);

 text1=text1+ch;

 flag=0;

 }

 else if(sp==0)

 {

 if(ch >=65 && ch< =90)

 ch=(char)(ch+32);

 text1=text1+ch;

 }

i++;

}while(i< len);

text1=text1.trim();

System.out.println("Name in short form="+text1);

}

}

Technical analysis of the string modification program

Blank spaces of the entered string is counted first using a do while loop in this program. Again each apphabets are accessed using another do while loop where the required modification is done. The first alphabet of the string acceesed is the initial character of the name and the character is converted into upper case is necessary and concatenated with another string object. Whenever any blank space in the string is encountered, the variable containing the number of blank spaces in the string is decreased by 1, a dot (.) is concatenated with the string object containing the modified string and another variable ‘flag’ is set to 1. This value indicates that blank space is encountered just one character before. So the alphabets when the value of flag is 1, is concatenated to the modified string object. These alphabets are those initial alphabets of middlename and surname. When the value of the variable holding the number of blank spaces becomes zero, it indicates that surname alphabets excepting the initial character is accessed, so they are converted in to lower case if required and attached to the modified string object.

Related Post:  BlueJ Programs on String/Sentence