Finding All Possible Consecutive Number Combinations Using BlueJ Program

Amout the program on number of combination

We have to take a number and find out the sum of consecutive numbers within that entered number which is equal to the entered number itself. For example – if the entered number is 15 the consecutive number combinations will be

1 2 3 4 5
4 5 6
7 8 

Codes of the program on number combination

import java.io.*;

class NumberCombonation

{

int no,sum=0,k,j,i;

BufferedReader br=new BufferedReader(new InputStreamReader(System.in));

 public void takeNumber()throws Exception

 {

System.out.println("Enter the number:");

no=Integer.parseInt(br.readLine());

 for(i=1;i<=no/2+1;i++)

 {

 sum=0;

  for(j=i;j<=no/2+1;j++)

  {

sum=sum+j;

if (sum==no)

break;

}

if(j<=no/2+1)

{

 for(k=i;k<=j;k++)

 System.out.print(" "+k);

 System.out.println();

}

}

}

public static void main(String args[])throws Exception

{

 NumberCombonation obj=new NumberCombonation ();

 obj.takeNumber();

}

}

Technical analysis of the number combination program

The outer loop starts from 1 and this loop is generates the starting number of consecutive number combination series and the first inner loop checks if the number combination is possible with that starting number. If a series is found, which is checked just outside the first inner loop, the second inner loop prints the consecutive number combination.

Related Post: BlueJ Programs on Number