BlueJ Program On Disarium Number

Input a number from keyboard and check whether it is Disarium or not.

What is Disarium Number

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A number will be called Disarium if sum of its digits powered with their respective position is equal with the number itself. 

Sample Input: 135

Output : It is a Disarium

(1^1+3^2+5^3 = 135, some other Disarium are 89, 175, 518 etc)

class Disarium

{

public void show(int n)

{

int c=1,rev,sum,x;

x=n;

sum=0;

rev=0;

while (n>0)

{

 rev=rev*10+n%10;

 n=n/10;

 }

 while(rev>0)

 {

  sum=sum+(int)Math.pow(rev%10,c);

  c++;

  rev=rev/10;

  }

  if(sum==x)

  System.out.println(x + " is DISARIUM");

  else

  System.out.println(x + " is not DISARIUM");

 }

public static void main(String args[]) throws Exception

{

Disarium ob=new Disarium ();

ob.show(275);

}

}

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