This is ICSE 2010 Computer Application Paper. All the questions are solved here. This page may be helpful to ICSE students.
SECTION – A (40 Marks)
Question 1.
(a)
Define the term Byte
Code. [2]
Ans: Byte code is a highly
optimized set of instructions designed to be executed by java runtime system.
( b)
What do you understand
by type conversion? [2]
Ans: Type conversion is the
technique of one type of data into the other type. There are two type of type
conversion – Implicit conversion and Explicit conversion. In implicit
conversion, lower type data is automatically converted into upper side and in
explicit conversion, one type of data is converted into the other type
forcefully.
(c)
Name two jump
statements and their use. [2]
And: break and continue are
two jump statements in java. In java, break can be used inside a loop and
switch statement to send the control out of the loop body or switch body.
Continue can be used
only inside a loop body and it starts premature iteration of the loop.
(d)
What is Exception ?
Name two Exception Handling Blocks. [2]
Ans: Exception is a run
time abnormality caused due to many reasons. Two exception handling blocks are
try…catch and throws.
(a)
Write two advantages
of using functions in a program. [2]
Ans: Two advantages of
using functions in a program can be defined as it breaks the program into
number of small modules and secondly it makes the program simple.
Question 2.
(a) State the purpose
and return data type of the following String functions:
[2]
(i)
indexOf ( ).
(ii)
CompareTo ( )
Ans: Return data type of
both the functions are int. The function indexOf() checks the existence of any
single character or a string in the invoking string object and returns the
first occurrence location if found otherwise it returns -1.
compareTo () checks
two strings for equality. If both the strings are same it returns 0. If the
invoking string is greater than the argument string it returns greater than 0
otherwise it returns less than 0.
(b) What is the result
stored in x, after evaluating the following expression [2]
int x = 5;
x = x++ *2 + 3 * –x;
Ans: -8
(a)
Differentiate between
static and non-static data members. [2]
Ans: static data members
are class members and so only one copy of such members are created for number
of objects of the class. The same static data member is shared by all objects.
For each objects of a
class, separate copy of non-static data members are created so each object has
it’s own copy of non-static data member.
(b)
Write the difference
between length and length ( ) functions. [2]
Ans: length is a data
member of array and it holds the number of elements stored in the array. length
() is a function of String class and return type of the function is int which
denotes the number of characters in the string object.
(c)
Differentiate between
private and protected visibility modifiers. [2]
Ans: private members are accessible within the
class only where as protected members are accessible within the class as well
as by sub classes.
Question 3
(a)
What do you understand
by data abstraction? Explain with an example.[2]
Ans: Data abstraction is the mechanism of binding data members and
function members together so that data members are safe from unauthorized
access. Function members acts on the data members and thus complexity of the
program is reduced.
A car is an object
which has many physical components which are the data members of the object.
Different functions like brake, horn etc are working on the physical components
and we are getting the result without knowing details about the mechanism.
(b) What will be the
output of the following code?
(i)
int
m=2;
[2]
int n=15;
for(int i = 1;
i<5 i="" o:p="">
m++; --n;
System.out.println(“m=”
+m);
System.out.println(“n=”+n);
Ans: m=6
n=14
(ii) char x =
‘A’ ; int m;
[2]
m=(x==’a’) ? ‘A’
: ‘a’;
System.out.println(“m=”+m);
Ans: m=97
Programming Section
Question 4.
Write a program to perform binary search on a
list of integers given below, to search for an element input by the user. If it
is found display the element along with its position, otherwise display the
message “Search element not found”. [15]
5,7,9,11,15,20,30,45,89,97
Ans:
import java.io.*;
class BSearch
{
int i,n,low,high,mid;
int
arr[]={5,7,9,11,15,20,30,45,89,97};
BufferedReader br=new
BufferedReader (new InputStreamReader (System.in));
public void input() throws Exception
{
System.out.println("Enter the value to
search:");
n=Integer.parseInt(br.readLine());
search();
}
void search()
{
low=0;high=9;
while(low<=high)
{
mid=(low+high)/2;
if(arr[mid]==n)
break;
else if(arr[mid]>n)
high=mid-1;
else
low=mid+1;
}
if(low<=high)
System.out.println("Element
Found.");
else
System.out.println("Search element not
found.");
}
public static void
main(String args[])throws Exception
{
BSearch ob=new
BSearch();
ob.input();
}
}
Question 5
Define a class ‘Student‘
described as below: [15]
Data members/instance
variables : name,age,m1,m2,m3 (marks in 3 subjects),
maximum, average
Member methods :
(i) A parameterized
constructor to initialize the date members.
(ii) To accept the
details of a student.
(iii) To compute the
average and the maximum out of three marks.
(iv) To display the
name, age, marks in three subjects, maximum and average.
Write a main method
to create an object of a class and call the above member methods.
Ans:
import java.io.*;
class Student
{
String name;
int
age,m1,m2,m3,maximum;
double average;
BufferedReader br=new
BufferedReader (new InputStreamReader (System.in));
Student(String n)
{
name=n;
}
public void input()
throws Exception
{
System.out.println("Enter the age of
"+name + ":");
age=Integer.parseInt(br.readLine());
System.out.println("Enter
the 1st subject marks of "+name + ":");
m1=Integer.parseInt(br.readLine());
System.out.println("Enter
the 2nd subject marks of "+name + ":");
m2=Integer.parseInt(br.readLine());
System.out.println("Enter
the 3rd subject marks of "+name + ":");
m3=Integer.parseInt(br.readLine());
}
void compute()
{
average=(double)(m1+m2+m3)/3;
if(m1>m2 && m1>m3)
maximum=m1;
else if(m2>m1 && m2>m3)
maximum=m2;
else
maximum=m3;
}
void show()
{
System.out.println("Name:"+name);
System.out.println("Age:"+age);
System.out.println("First
Subject:"+m1);
System.out.println("Second
Subject:"+m2);
System.out.println("Third
Subject:"+m3);
System.out.println("Maximum
marks:"+maximum);
System.out.println("Average
marks:"+average);
}
public static void
main(String args[])throws Exception
{
String n;
BufferedReader br=new
BufferedReader (new InputStreamReader (System.in));
System.out.println("Name
of the student:");
n=br.readLine();
Student ob=new
Student(n);
ob.input();
ob.compute();
ob.show();
}
}
Question 6
Shasha Travels Pvt.
Ltd. gives the following discount to its customers: [15]
Ticket amount
Discount
Above Rs 70000
18%
Rs 55001 to Rs
70000
16%
Rs 35001 to Rs
55000
12%
Rs 25001 to Rs
35000
10%
less than Rs
25001
2%
Write a program to
input the name and ticket amount for the customer and calculate the discount
amount and net amount to be paid. Display the output in the following format
for each customer :
SL.
NO.
|
Name
|
Ticket
charges
|
Discount
|
Net
amount
|
|
|
|
|
|
(Assume that there are
15 customers, first customer is given the serial no (SlNo.) 1, next customer 2
……… and so on.
import java.io.*;
class Fare
{
String name[]=new String[5];
int amount[]=new int[5];
int i;
double discount,net;
BufferedReader br=new
BufferedReader (new InputStreamReader (System.in));
public void input()
throws Exception
{
for(i=0;i<15 i="" o:p="">
{
System.out.println("Enter the
name:");
name[i]=br.readLine();
System.out.println("Enter
the amount for ticket in Rs.:");
amount[i]=Integer.parseInt(br.readLine());
}
}
void show()
{
System.out.println("SL.
NO. Name Ticket charges Discount
Net amount");
for(i=0;i<15 i="" o:p="">
{
if(amount[i]>70000)
{
discount= amount[i]*18.0/100;
net=amount[i]-discount;
}
else if(amount[i]>=55001 &&
amount[i]<=70000)
{
discount= amount[i]*16.0/100;
net=amount[i]-discount;
}
else if(amount[i]>=35001 &&
amount[i]<=55000)
{
discount= amount[i]*12.0/100;
net=amount[i]-discount;
}
else if(amount[i]>=25001 &&
amount[i]<=35000)
{
discount= amount[i]*10.0/100;
net=amount[i]-discount;
}
else
{
discount= amount[i]*2.0/100;
net=amount[i]-discount;
}
System.out.println((i+1)+
"\t\t"+name[i]+ " "+amount[i]+ " "+ discount+
" "+net);
}
}
public static void
main(String args[])throws Exception
{
Fare ob=new Fare ();
ob.input();
ob.show();
}
}
Question 7
Write a menu driven
program to accept a number and check and display whether it is a Prime
Number or not OR an Automorphic Number or not. (Use
switch-case statement). [15]
(a) Prime
number : A number is said to be a prime number if it is divisible
only by 1 and itself and not by any other number.
Example : 3,5,7,11,13 etc.
(b) Automorphic
number : An automorphic number is the number which is contained in the
last digit(s) of its square.
Example: 25 is an automorphic number as its
square is 625 and 25 is present as the last two digits.
import java.io.*;
class Library
{
public void automorphic(int n)
{
int
no,digit=0,sq,rev=0;
no=n;
do
{
digit++;
no=no/10;
} while(no!=0);
sq=n*n;
do
{
rev=rev*10+sq%10;
sq=sq/10;
digit--;
if(digit==0)
break;
}
while(true);
no=rev;
rev=0;
while(no!=0)
{
rev=rev*10+no%10;
no=no/10;
}
if(n==rev)
System.out.println(n+" is an
Automorphic number");
else
System.out.println(n+" is not an
Automorphic number");
}
public void prime(int
n)
{
int i;
for(i=2;i
{
if(n%i==0)
break;
}
if (i==n)
System.out.println(n+"
is a prime number");
else
System.out.println(n+"
is not a prime number");
}
public static void
main(String args[])throws Exception
{
BufferedReader br=new
BufferedReader(new InputStreamReader(System.in));
int ch,n;
Library ob=new
Library();
System.out.println("Enter
1 for automorphic number and 2 for prime number:");
ch=Integer.parseInt(br.readLine());
System.out.println("Enter
the number:");
n=Integer.parseInt(br.readLine());
switch(ch)
{
case 1:
ob.automorphic(n);
break;
case 2:
ob.prime(n);
break;
default:
System.out.println("Wrong
Choice:");
}
}
}
Question 8.
Write a program to
store 6 element in an array P, and 4 elements in an array Q and produce a
third array R, which does not contain common
values of array P and Q. Display the resultant array [15]
EXAMPLE:
INPUT
OUTPUT
P[ ]
Q [ ]
R [ ]
4
19
4
6
23
6
1
7
1
2
8
2
3 3
10 10
19
23
7
8
import java.io.*;
class Merge
{
int p[]=new int[6];
int q[]=new int[4];
int r[]=new int[10];
int i,j,x=0,y=0,k;
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
public void takeValues() throws Exception
{
System.out.println("For 1st array:");
for(i=0;i< 6;i++)
{
System.out.println("Value:");
p[i]=Integer.parseInt(br.readLine());
}
System.out.println("For 2nd array:");
for(i=0;i< 4;i++)
{
System.out.println("Value:");
q[i]=Integer.parseInt(br.readLine());
}
System.out.print("First array:");
for(i=0;i< 6;i++)
System.out.print(" "+p[i]);
System.out.println();
System.out.print("Second array:");
for(i=0;i< 4;i++)
System.out.print(" "+q[i]);
for(i=0;i< 6;i++)
{
for(j=0;j< 4;j++)
{
if(q[j]==p[i])
break;
}
if(j==4)
{
r[x++]=p[i];
}
else
{
for(k=j;k< 3;k++)
{
q[k]=q[k+1];
}
y++;
}
}
for(i=0;i< 4;i++)
{
for(j=0;j< 10;j++)
{
if(q[i]==r[j])
break;
}
if(j==x)
{
r[x++]=q[i];
}
}
}
public void show()
{
System.out.println();
System.out.print("The resultant array:");
for(i=0;i< x;i++)
System.out.print(" "+r[i]);
}
public static void main(String args[])throws Exception
{
Merge ob=new Merge ();
ob.takeValues();
ob.show();
}
}
Question 9
Write a program to
input a string in uppercase and print the frequency
of each character. [15]
INPUT : COMPUTER HARDWARE
OUTPUT :
CHARACTERS
FREQUENCY
A
2
C
1
D
1
E
2
H
1
M
1
O
1
P
1
R
3
T
1
U
1
W
1
import
java.io.*;
class
Frequency
{
String
s;
int
i,len,j,c;
char
ch[],ch1;
BufferedReader
br=new BufferedReader(new InputStreamReader(System.in));
public
void takeString() throws Exception
{
System.out.println("Enter
the sentence:");
s=br.readLine().toUpperCase();
ch=new
char[s.length()];
}
public void show()
{
len=s.length();
for(i=0;i< len;i++)
ch[i]=s.charAt(i);
for(i=0;i< len-1;i++)
{
for(j=i+1;j< len;j++)
{
if(ch[i]>ch[j])
{
ch1=ch[i];
ch[i]=ch[j];
ch[j]=ch1;
}
}
}
ch1=ch[0];
c=1;
System.out.println("Characters Frequency");
for(i=1;i< len;i++)
{
if(ch1==ch[i])
c++;
else
{
System.out.println(ch1+ " \t\t\t\t"+c);
ch1=ch[i];
c=1;
}
}
}
public
static void main(String args[])throws Exception
{
Frequency
ob=new Frequency ();
ob.takeString();
ob.show();
}
}