BlueJ Program on displaying day name from the entered date in specific format

Here is the BlueJ Program for ISC Students.

Write a program to accept a date in a specific string format (dd/mm/yyyy) and accept the name of the day on 1st January of the corresponding year. Find the day for the given date.

Example:
Input:
Enter the date ( in dd/mm/yyyy) format: 5/7/2001
Enter the Day on 1st January in this year: Monday

Output:
5/7/2001 : Thursday

import java.io.*;
class Date1
{
int arr[]={31,28,31,30,31,30,31,31,30,31,30,31};
BufferedReader br;
String str1,day,day1;
int x,i,dayno,mon,yr,leap1;
public static void main(String args[])throws IOException
{
Date1 ob=new Date1 ();
ob.take();
ob.show();
}
Date1 ()
{
br=new BufferedReader(new InputStreamReader(System.in));
}
public void take()throws IOException
{
System.out.println("Enter the date ( in dd/mm/yyyy) format:");
day=br.readLine().trim();
day1=day;
i=day.indexOf("/");
dayno=Integer.parseInt(day.substring(0,i));
day=day.substring(i+1);
i=day.indexOf("/");
mon=Integer.parseInt(day.substring(0,i));
day=day.substring(i+1);
yr=Integer.parseInt(day);
leap1=0;
if(mon>2)
leap1=leap(yr);
System.out.println("Enter the Day on 1st January in this year:");
str1=br.readLine().trim();
}
int leap(int p)
{
if(p%100==0 && p%400==0)
return 1;
else if(p%100!=0 && p%4==0)
return 1;
else
return 0;
}
void show ()
{
if (str1.equalsIgnoreCase("Sunday"))
x=1;
else if (str1.equalsIgnoreCase("Monday"))
x=2;
else if (str1.equalsIgnoreCase("Tuesday"))
x=3;
else if (str1.equalsIgnoreCase("Wednesday"))
x=4;
else if (str1.equalsIgnoreCase("Thursday"))
x=5;
else if (str1.equalsIgnoreCase("Friday"))
x=6;
else if (str1.equalsIgnoreCase("Saturday"))
x=7;

for(i=0;i< mon-1;i++)

dayno=dayno+arr[i];

dayno=dayno+leap1;

for(i=0;i< dayno-1;i++)

{

 x++;

 if(x==8)

 x=1;

 }

 System.out.println(day1+ ":");

switch(x)

{

 case 1:

 System.out.println("Sunday");

 break;

 case 2:

 System.out.println("Monday");

 break;

 case 3:

 System.out.println("Tuesday");

 break;

 case 4:

 System.out.println("Wednesday");

 break;

 case 5:

 System.out.println("Thursday");

 break;

 case 6:

 System.out.println("Friday");

 break;

 case 7:

 System.out.println("Saturday");

 break;

}

 }

 }

 Here in this BlueJ program the array ‘arr’ holds the number of days of each month. ‘take()’ function takes the date and day name of 1st January of the specific year. It also breaks the date into day, month and year. If the month is greater than 2 ( Means minimum March), from the end of the body of the function it calls a function ‘leap()’. It returns ‘1’ if the year is leap year other wise returns ‘0’.

Within ‘show()’ function we initialize a variable ‘x’ with 1 if the day name is Sunday, 2 if the day name is Monday and so on. That means in our BlueJ program ‘x’ holds the day number of the 1st January of the specific year. Then using a for loop, count the total number of days from 1st January to the specified date and ‘x’ is utilized to hold the day number of the specific date.

Related Post: BlueJ Programs on Numeric Array
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