We have done programs on C structure where structure member are normally primitive data members. Now we will see how to use structure variables as a member of another structure.
#include< stdio.h>
struct cal
{
int feet;
float inch;
};
struct Room
{
struct cal length;
struct cal width;
};
void main()
{
struct Room ob;
float l,w;
clrscr();
ob.length.feet=10;
ob.length.inch=2.5;
ob.width.feet=10;
ob.width.inch=2.5;
l=ob.length.feet+ob.length.inch/12;
w=ob.width.feet+ob.width.inch/12;
l=l*w;
printf("Area of the Room %.2f",l);
getch();
}
Another program on structure within structure.
# include< stdio.h>
struct Addr
{
char street[30];
char city [30];
char state[20];
long pin;
};
struct Customer
{
char name[20];
char account[10];
char profession[30];
struct Addr address;
};
void main()
{
struct Customer *list[100];
int i, n;
clrscr();
printf("\n Input number of record you want to process: ");
scanf("%d", &n);
printf("\n Input the information of customer\n");
for(i=0; i< n; i++)
{
fflush(stdin);
printf("\n Name: ");
gets(list[i]->name);
printf("\n Account Number:");
gets(list[i]->account);
printf("\n Profession:");
gets(list[i]->profession);
printf("\n*** Address***");
printf("\n**************\n");
printf("\n Street:");
gets(list[i]->address. street);
printf("\n City:");
gets(list[i]->address. city);
printf("\n State:");
gets(list[i]->address. state);
printf("\n Pin Code:");
scanf("%ld", &list[i]->address. pin);
clrscr();
}
for(i= 0; i< n; i++)
{
printf("\n List of the customer");
printf("\n ********************\n");
printf("\n Name: %s", list[i]->name);
printf("\n Account Number: %s", list[i]->account);
printf("\n Profession: %s", list[i]->profession);
printf("\n *** Address ***");
printf("\n----------------");
printf("\n Street: %s", list[i]->address. street);
printf("\n City: %s", list[i]->address. city);
printf("\n State: %s", list[i]->address. state);
printf("\n Pin code: %ld", list[i]->address. pin);
printf("\n*******************");
printf("\nPress any key...........");
getch();
clrscr();
}
}
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