BlueJ Program On Arranging The Digits Of A Number In Ascending Order

This is a BlueJ program  on rearranging the digits of number in ascending order. Suppose the entered number is 2314 then the output will be 1234.

Codes of the program

import java.io.*;

class Num1

{

int arr[]=new int[10];

int i,j,t,n,x=0,rev=0;

BufferedReader br=new BufferedReader(new InputStreamReader(System.in));

public void take() throws IOException

{

 System.out.print("Enter the Number:");

 n=Integer.parseInt(br.readLine());

System.out.println("Entered Number="+n);

while(n>0)

{

 arr[x++]=n%10;

 n=n/10;

}

for(i=0;i< x-1;i++)

{

for(j=i+1;j< x;j++)

{

if(arr[i]>arr[j])

{

 t=arr[i];

 arr[i]=arr[j];

 arr[j]=t;

}

}

}

for(i=0;i< x;i++)

{

 rev=rev*10+arr[i];

}

System.out.println("The number in modified form="+rev);

}

public static void main(String args[]) throws Exception

{

 Num1 ob=new Num1();

 ob.take();

}

}

Related Post: BlueJ Programs on Numeric Array

In this program, digits from the entered number are retrieved and stored in an array. The array is then sorted in ascending order and from the array the digits are retrieved and a new number is formed.

Sample input and output of the program

Enter the Number:261

Entered Number=261

The number in modified form=126

Enter the Number:9715

Entered Number=9715

The number in modified form=1579