Armstrong Number Program Using While Loop

Here is the program to check a number whether it is Armstrong number or not using while loop.

 import java.io.*;

class A

{

int n;

BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

public void take() throws Exception

{

System.out.println("Enter the number:");

n=Integer.parseInt(br.readLine());

if(no(n))

System.out.println(n + " is an armstrong number");

else

System.out.println(n + " is not an armstrong number");

}

private boolean no(int x)

{

int f=0,y,m;

m=x;

while(x>0)

{

y=x%10;

f=f+y*y*y;

x=x/10;

}

if(m==f)

return true;

else

return false;

}

public static void main(String args[]) throws Exception

{

A ob=new A();

ob.take();

}

}

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