Check if a number is an Unusual Number or not Given a positive integer N. The task is to check if N is an unusual number or not. Print ‘YES’ if M is an unusual number else print ‘NO’.
Unusual number : In Mathematics, an unusual number is a natural number whose greatest prime factor is strictly greater than square root of n.
The first few unusual numbers are –
2, 3, 5, 6, 7, 10, 11, 13, 14, 15, 17, 19, 20, 21, 22, 23, 26, 28, 29, 31, 33, 34, 35, 37, 38, 39, 41, 42, 43, 44, 46, 47, 51
import java.io.*;
class Str3
{
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
void take() throws Exception
{
int p,i,n;
System.out.print("\nEnter any number: ");
n=Integer.parseInt(br.readLine());
for(i=n;i>=2;i--)
{
if(n%i==0 && prime(i))
break;
}
p=i;
if(p>(int)Math.sqrt(n))
System.out.println("It is unusual number");
else
System.out.println("It is not an unusual number");
}
private boolean prime(int n)
{
int i;
for(i=2;i<n;i++)
{
if(n%i==0)
break;
}
if(i==n)
return true;
else
return false;
}
public static void main(String args[])throws Exception
{
Str3 ob=new Str3();
ob.take();
}
}
2, 3, 5, 6, 7, 10, 11, 13, 14, 15, 17, 19, 20, 21, 22, 23, 26, 28, 29, 31, 33, 34, 35, 37, 38, 39, 41, 42, 43, 44, 46, 47, 51
import java.io.*;
class Str3
{
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
void take() throws Exception
{
int p,i,n;
System.out.print("\nEnter any number: ");
n=Integer.parseInt(br.readLine());
for(i=n;i>=2;i--)
{
if(n%i==0 && prime(i))
break;
}
p=i;
if(p>(int)Math.sqrt(n))
System.out.println("It is unusual number");
else
System.out.println("It is not an unusual number");
}
private boolean prime(int n)
{
int i;
for(i=2;i<n;i++)
{
if(n%i==0)
break;
}
if(i==n)
return true;
else
return false;
}
public static void main(String args[])throws Exception
{
Str3 ob=new Str3();
ob.take();
}
}
Other Programs On Numbers: CLICK HERE
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