Java Program To Check Boring Number

  Write a program in java to accept a number from user and check whether the number us a boring number or not.

Boring number is a positive number having all the digits at even position in the number as even and the digits at odd position odd

 

import java.util.*;
class BoringNumber
{
int n,rev,f;
Scanner sc=new Scanner(System.in);
public void take()
{
   System.out.print("\nEnter The Number:");
   n=sc.nextInt();
   display();
}
private void display()
{
   rev=0;
   f=1;
    System.out.print("\nEntered Number is:"+n);
   while(n>0)
   {
        rev=rev*10+n%10;
        n=n/10;
   }
   while(rev>0)
   {
       int d=rev%10;
       if(f%2!=d%2)
       break;
       rev=rev/10;
       f++;
   }
   if(rev>0)
   System.out.print("\nEntered Number is not a boring number");
   else
   System.out.print("\nEntered Number is a boring number");
}
public static void main(String args[])
{
BoringNumber ob=new BoringNumber();
ob.take();
}
}         

Sample Input Output

Enter The Number:1234
Entered Number is:1234
Entered Number is a boring number

Enter The Number:1321
Entered Number is:1321
Entered Number is not a boring number